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Direct Proportion

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In direct proportion doubling one quantity doubles the other

The same amount for each one

Pens cost $3 each. 1 pen costs $3, 2 pens cost $6 and 3 pens cost $9. Every extra pen adds the same $3 to the cost, because every pen costs the same.

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The cost of 1, 2 and 3 pens. Each bar is $3 taller than the one before.

Double one and the other doubles

2 pens cost $6. Double the number of pens to 4, and the cost doubles too: 4 pens cost $12. Multiply the number of pens by 3 and the cost is multiplied by 3: 6 pens cost 3 × $6 = $18. Halve the number of pens and the cost halves.

When two quantities change like this, so that multiplying one by any number multiplies the other by the same number, the two quantities are in direct proportion. Here the cost is in direct proportion to the number of pens.

Another way to see it: divide each cost by its number of pens, and you always get the same answer. $6 ÷ 2 = $3, $12 ÷ 4 = $3, $18 ÷ 6 = $3. The ratio of cost to pens stays fixed at 3 : 1.

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2 pens cost $6 and 4 pens cost $12: twice as many pens, twice the cost.

A straight line that starts at zero

Plot the number of pens against the cost and the points lie on a straight line. The line starts at 0, because 0 pens cost $0.

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The cost of 0 to 4 pens: a straight line from $0, rising $3 for every pen.

Growing steadily is not enough

A taxi charges $5 to start the ride and then $2 for every kilometer. 1 km costs $7, 2 km cost $9 and 4 km cost $13. Each extra kilometer adds the same $2, but doubling the distance from 2 km to 4 km does not double the cost: $9 doubled is $18, not $13. The cost is not in direct proportion to the distance, because of the $5 you pay before the taxi has moved.

On a graph the line is still straight, but it starts at $5, not at 0. Two quantities in direct proportion always start together at 0.

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The taxi fare for 0 to 4 km: a straight line that starts at $5, so the fare is not in direct proportion to the distance.

The usual mistakes

Adding the extra number of items instead of scaling. If 2 pens cost $6, then 4 pens do not cost $6 + 2 = $8. Each pen costs $3, so 4 pens cost 4 × $3 = $12.

Adding the number of items to the price of one. 4 pens at $3 each is 4 × 3 = $12, not 4 + 3 = $7.

Pricing one item too few. 4 pens cost 4 × $3 = $12. $9 is the cost of only 3 of them.

Distance at a steady speed

When two cyclists ride for the same length of time, the distance each one covers is in direct proportion to their speed: twice the speed covers twice the distance. The next problem uses this to find how far apart two cyclists are after they set off together from the same place.

Speed · Two Cyclists Set Off Together at Different Speeds

QuestionKeith and Leonard set off on their bikes at the same time from the same gate and rode along a park trail in the same direction. Keith rode at 24 km/h and Leonard rode at 16 km/h. (a) How far apart were they after 45 minutes? (b) How long after they set off were they 10 km apart?

  1. 1.Keith and Leonard ride for the same time, so their distances are in the same ratio as their speeds: 24 : 16 = 3 : 2.

    Keith3 units24 km/hLeonard2 units16 km/h
    Same start and same time, so the distances are in the ratio of the speeds: 24 : 16 = 3 : 2.
  2. 2.So at any moment Keith has ridden 3 units while Leonard has ridden 2 units. The gap between them is 1 unit.

    Keith3 units24 km/hLeonard2 units16 km/hgap 1 unit
    At any moment Keith has ridden 3 units and Leonard 2 units. The gap is 1 unit.
  3. 3.In 1 hour Keith rides 24 km, which is 3 units, so 1 unit is 24 ÷ 3 = 8 km. The gap grows by 8 km every hour.

    Keith18 km24 km/h · 45 minLeonard12 km16 km/h · 45 mingap 6 km
    In 1 hour Keith rides 24 km, which is 3 units, so 1 unit is 24 ÷ 3 = 8 km: the gap grows 8 km each hour.
  4. 4.(a) 45 minutes is 34 of an hour, so after 45 minutes the gap is 34 × 8 = 6 km.

    Keith18 km24 km/h · 45 minLeonard12 km16 km/h · 45 mingap 6 km
    (a) 45 minutes is 34 of an hour: the gap is 34 × 8 = 6 km.
  5. 5.(b) A gap of 10 km takes 10 ÷ 8 = 114 hours, which is 1 hour 15 minutes. Check: in 114 hours Keith rides 30 km and Leonard rides 20 km, and 30 − 20 = 10 km.

    Keith18 km24 km/h · 45 minLeonard12 km16 km/h · 45 mingap 6 kma 10 km gap: 10 ÷ 8 = 1.25 h, which is 1 h 15 min
    (b) A gap of 10 km takes 10 ÷ 8 = 114 hours, which is 1 hour 15 minutes.

Answer: (a) 6 km; (b) 1 hour 15 minutes

Watch out for

  • Answering part (a) with Keith's distance alone: 24 × 34 = 18 km. That is how far Keith is from the gate. Leonard has also moved 16 × 34 = 12 km, so they are only 18 − 12 = 6 km apart.
  • Reading 1.25 hours as 1 hour 25 minutes. The 0.25 is a quarter of an hour, and a quarter of 60 minutes is 15 minutes.

Your turn

1.If 2 cost 6, what do 6 cost? 

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